python提取特定格式的数据的操作方法

import tkinter as tk
from tkinter import filedialog, messagebox
import pandas as pd
import os

source_df = pd.read_excel(file_path, sheet_name=None, index_col=None)
source_data = source_df['一格一案']

result_data = {
    '网格编号': source_data.iloc[1, 1],
    '责任段': source_data.iloc[1, 3],
    ...
}

risk_check_path = "\n".join(source_data.iloc[9:19, 1].dropna().astype(str))
result_data['五、风险项点检查路径'] = risk_check_path

result_df = pd.DataFrame(all_data)
result_df.to_excel(output_file_path, index=False)

root = tk.Tk()
root.title("Excel 转换工具")
root.geometry(f'{window_width}x{window_height}+{position_right}+{position_top}')

title_label = tk.Label(root, text="Excel 转换工具", font=("Arial", 18))
title_label.pack(pady=20)
select_button = tk.Button(root, text="选择 Excel 文件", command=select_files, font=("Arial", 12))
select_button.pack(pady=10)

file_paths = filedialog.askopenfilenames(filetypes=[("Excel 文件", "*.xlsx")])
output_file_path = filedialog.asksaveasfilename(defaultextension=".xlsx", filetypes=[("Excel 文件", "*.xlsx")])

def transform_to_result_format_specific(source_data, source_file_path):
    risk_check_path = "\n".join(source_data.iloc[9:19, 1].dropna().astype(str))
    result_data = { ... }
    return result_data

def select_files():
    file_paths = filedialog.askopenfilenames(filetypes=[("Excel 文件", "*.xlsx")])
    all_data = []
    for file_path in file_paths:
        source_df = pd.read_excel(file_path, sheet_name=None, index_col=None)
        source_data = source_df['一格一案']
        transformed_data = transform_to_result_format_specific(source_data, file_path)
        all_data.append(transformed_data)
    result_df = pd.DataFrame(all_data)
    output_file_path = filedialog.asksaveasfilename(defaultextension=".xlsx", filetypes=[("Excel 文件", "*.xlsx")])
    if output_file_path:
        result_df.to_excel(output_file_path, index=False)
        messagebox.showinfo("成功", "文件已成功转换并保存。")