python对列表中任意两个数进行操作的实现

def list_any_two_mul(mylist):
     num = 1
     temp = []
     for i in mylist[:-1]:
         temp.append([i * j for j in mylist[num:]])
         num = num + 1
     # 把多个列表变成只有一个列表
     results = [y for x in temp for y in x]
     return results

def list_any_two_and(mylist2):
     temp2 = []
     num2 = 1
     # 先对列表中的元素两两相与
     for i in mylist2[:-1]:
         temp2.append([cv2.bitwise_and(i, j) for j in mylist2[num2:]])
         num2 = num2 + 1

     # 再把相与后的结果放在一个列表中
     results2 = []
     for i in range(len(temp2)):
         for j in range(len(temp2[i])):
             results2.append(temp2[i][j])
     return results2

>>> import numpy as np
>>> a=np.arange(1,13).reshape(3,4)
>>> a
>>> array([[ 1,  2,  3,  4],
       [ 5,  6,  7,  8],
       [ 9, 10, 11, 12]])
>>> b=np.arange(13,25).reshape(3,4)
>>> b
>>> array([[13, 14, 15, 16],
       [17, 18, 19, 20],
       [21, 22, 23, 24]])
>>> c=np.random.randint(0,2,(3,4))
>>> c
>>> array([[0, 1, 1, 1],
       [0, 0, 1, 1],
       [0, 0, 1, 1]])
>>> d=[a,b,c]
>>> g=list_any_two_and(g)
>>> g
>>> [array([[1, 2, 3, 0],
        [1, 2, 3, 0],
        [1, 2, 3, 8]], dtype=int32), array([[0, 0, 1, 0],
        [0, 0, 1, 0],
        [0, 0, 1, 0]], dtype=int32), array([[0, 0, 1, 0],
        [0, 0, 1, 0],
        [0, 0, 1, 0]], dtype=int32)]