Python正则表达式如何匹配特殊字符串

strings = ['result-2023-08-18-6g1s1ch-DB9909',  
           'result-2023-08-18-4g1s3ch-DB9909',
           'result-2023-08-18-1g4s1ch-DB9909',
           'result-2023-08-18-1g1s1ch-DB9909']

pattern = r'(\d+)([Gg])(\d+)([Ss])(\d+)([Cc][Hh])' 

results = []
for s in strings:
    match = re.search(pattern, s)
    if match:
        print(match.group())
        g = match.group(2)  #匹配第2个括号的内容
        s = match.group(4)  #匹配第4个括号的内容
        ch = match.group(6) #匹配第6个括号的内容
        string = match.group(1) + g + match.group(3) + s + match.group(5) + ch
        results.append(string)
print(results)


db_pattern = r'([Dd][Bb])(\d+)'

match = re.search(db_pattern, strings[0])
if match:
    print(match.group())
    db = match.group(1)      #匹配第2个括号的内容
    number = match.group(2)  #匹配第4个括号的内容
    db_number = db + number

fullDump_pDevice00000286923A19B0_frame000_1g1s1ch.gfxbench_inst2_F535

frame000_1g1s1ch.gfxbench_inst2_F535

import re

s = "fullDump_pDevice00000286923A19B0_frame000_1g1s1ch.gfxbench_inst2_F535" 

# Match the prefix to remove
prefix_pattern = r'^fullDump_pDevice\d+_'

# Use sub() to remove the matched prefix
result = re.sub(prefix_pattern, '', s)

print(result)

fullDump_pDevice00000286923A19B0_frame000_1g1s1ch.gfxbench_inst2_F535

s = "fullDump_pDevice0000028fd3B19D0_frame000_1g1s1ch.gfxbench_inst2_F535" 
prefix_pattern = r'^fullDump_pDevice(\d+)([A-Za-z0-9]+)_'
new = re.sub(prefix_pattern, "", s)
print(new)