基于Python将JSON字符串转换为字典

import json

# JSON 字符串
json_str = '{"name": "张三", "age": 25, "city": "北京"}'

# 转换为字典
data_dict = json.loads(json_str)

print(data_dict)
print(type(data_dict))  # <class 'dict'>
print(data_dict['name'])  # 张三

import json

# 示例 JSON 字符串
json_string = '''
{
    "name": "李四",
    "age": 30,
    "hobbies": ["阅读", "游泳", "编程"],
    "address": {
        "street": "中山路123号",
        "city": "上海"
    },
    "is_student": false
}
'''

# 转换为字典
data = json.loads(json_string)

# 访问数据
print(f"姓名: {data['name']}")
print(f"年龄: {data['age']}")
print(f"爱好: {data['hobbies']}")
print(f"城市: {data['address']['city']}")
print(f"是否学生: {data['is_student']}")

# 遍历字典
for key, value in data.items():
    print(f"{key}: {value}")

import json

json_str = '{"name": "王五", "age": 28'  # 缺少闭合括号，无效JSON

try:
    data = json.loads(json_str)
    print("转换成功:", data)
except json.JSONDecodeError as e:
    print(f"JSON解析错误: {e}")
    print(f"错误位置: 行 {e.lineno}, 列 {e.colno}")

import json

# 从文件读取 JSON
with open('data.json', 'r', encoding='utf-8') as f:
    data = json.load(f)  # 注意是 load() 不是 loads()
    
print(data)

# 确保正确处理中文
json_str = '{"name": "张三"}'
data = json.loads(json_str)
print(data['name'])  # 正常显示中文

# 输出时保持中文
print(json.dumps(data, ensure_ascii=False))  # {"name": "张三"}

import json

data = {
    "name": "赵六",
    "age": 35,
    "city": "广州"
}

# 转换为 JSON 字符串
json_str = json.dumps(data, ensure_ascii=False, indent=2)
print(json_str)