C++时间戳转换成日期时间的步骤和示例代码

 /* File name: ts2tm.c
 Converts an decimal timestamp to human-readable format
 by sillyboard(sillyboard@tom.com)
*/
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
struct date_time
{
 short dt_year;
 short dt_month;
 short dt_day;
 short dt_hour;
 short dt_minute;
 short dt_second;
}dt;

short bits_per_field[6] = {7, 4, 5, 5, 6, 5};

int main(int argc, char** argv)
{
 long timestamp;
 int i, j;
 unsigned long mask = 0x80000000;
 short bit;
 int accum;
 short* walker;
 if (argc != 2)
 {
  fprintf(stderr, "Usage: %s decimal-timestamp/n", argv[0]);
  exit(1);
 }

 timestamp = atol(argv[1]);
 walker = &dt;
 for (i = 0; i < 6; i ++)
 {
  accum = 0;
  for (j = 0; j < bits_per_field[i]; j ++)
  {
   bit = (timestamp & mask) ? 1 : 0;
   if (bit)
   {
    accum += pow(2, bits_per_field[i] - 1 - j);
   }
   mask = mask >> 1;
  }
  *walker ++ = accum;
 }

 dt.dt_second <<= 1;

 printf("%s/t", argv[1]);
 printf("%d-%d-%d %d:%d:%d/n", dt.dt_year + 1980, dt.dt_month,
  dt.dt_day, dt.dt_hour, dt.dt_minute, dt.dt_second);
 return;
}