C语言 坐标移动详解及实例代码

起点（0,0）
 
+  A10  = （-10,0）
 
+  S20  = (-10,-20)
 
+  W10 = (-10,-10)
 
+  D30 = (20,-10)
 
+  x  = 无效
 
+  A1A  = 无效
 
+  B10A11  = 无效
 
+ 一个空 不影响
 
+  A10 = (10,-10)
 

#include<iostream> 
#include<string> 
using namespace std; 
 
bool isValid(string s, char &key, int &step){ 
  if (s.size()<2 || s.size()>3)return false; 
  if (s[0] != 'A' && s[0] != 'D' && s[0] != 'W' && s[0] != 'S') 
    return false; 
  key = s[0]; 
  if (s.size() == 2 && s[1] >= '0' && s[1] <= '9'){ 
    step = s[1] - '0'; 
    return true; 
  } 
  if (s.size() == 3 && s[1] >= '0' && s[1] <= '9' && s[2] >= '0' && s[2] <= '9'){ 
    step = (s[1] - '0') * 10 + (s[2] - '0'); 
    return true; 
  } 
  return false; 
} 
 
 
void caculator(string s, int &x, int &y, char key, int step){ 
  switch (key){ 
  case 'A': 
    x -= step; 
    break; 
  case 'D': 
    x += step; 
    break; 
  case 'W': 
    y += step; 
    break; 
  case 'S': 
    y -= step; 
    break; 
  } 
  return; 
} 
 
int main(){ 
  string str; 
  while (cin >> str){ 
    int x = 0; 
    int y = 0; 
    int i = 0; 
    while (i<str.size()){ 
      string temp; 
      char key; 
      int step; 
      while (str[i] != ';'){ 
        temp.push_back(str[i]); 
        i++; 
      } 
      if (isValid(temp, key, step)) 
        caculator(temp, x, y, key, step); 
      i++; 
    } 
    cout << x << ',' << y<<endl; //must add endl(wtf...,waste time) 
  } 
  return 0; 
}