C++ 中lambda表达式的编译器实现原理

#include <stdlib.h> 
#include <stdio.h> 
//1. 无参数 
auto hello = [] () {printf( "Hello world!\n");}; 
// 2. 一个参数 
auto hello_int = [] (int val){ printf("the value is %d\n", val); }; 
int main(int argc, char **argv) { 
 hello(); 
 hello_int(argc); 
 // 3. 带捕获列表的lambda表达式 
 auto lambda = [argc, argv]() {printf("param: %d, path is:%s\n", argc, argv[0]);}; 
 lambda(); 
 return 0; 
}

$_0::operator()(void)  
$_1::operator()(int) 
main::$_2::operator() const(void) 

#include <stdlib.h> 
#include <stdio.h> 
class $_0 { 
public: 
 void operator() { 
 printf( "Hello world!\n"); 
 } 
}; 
class $_1 { 
public: 
 void operator(int va) { 
  printf("the value is %d\n", val); 
 } 
}; 
class main::$_2 { 
public: 
 main::$_2(int i, char **v): argc(i), argv(v) {} 
 //带捕获列表的，不能修改捕获列表... 
 void operator() const { 
 printf("param: %d, path is:%s\n", argc, argv[0]); 
 } 
private: 
 int argc; 
 char **argv; 
} 
int main(int argc, char **argv) { 
 $_0 hello; 
 hello(); 
 $_1 hello_int; 
 hello_int(argc); 
 main::$_2 lambda(argc, argv); 
 lambda(); 
 return 0; 
}