Python生成随机数组的方法小结

>>> import random
>>> random.randint(1,10)
5
>>> random.randint(1.0, 10.0)
5

>>> random.random()
0.9983625479554628

>>> random.uniform(1,5.0)
2.917249424176132
>>> random.uniform(9.9, 2)
3.4288029275359024

>>> random.randrange(1, 100, 2) #返回[1,100]之间的奇数
95
>>> random.randrange(100, 1, -2) #返回[100,1]之间的偶数
46

import random
def random_int_list(start, stop, length):
  start, stop = (int(start), int(stop)) if start <= stop else (int(stop), int(start))
  length = int(abs(length)) if length else 0
  random_list = []
  for i in range(length):
    random_list.append(random.randint(start, stop))
  return random_list

>>> random_int_list(1,100,10)
[54, 13, 6, 89, 87, 39, 60, 2, 63, 61]

import numpy as np
>>> np.random.rand(10)
array([ 0.56911206, 0.99777291, 0.18943144, 0.19387287, 0.75090637,
    0.18692814, 0.69804514, 0.48808425, 0.79440667, 0.66959075])

>>> np.random.randn(10)
array([-1.6765704 , 0.66361856, 0.04029481, 1.19965741, -0.57514593,
    -0.79603968, 1.52261545, -2.17401814, 0.86671727, -1.17945975])

>>> np.random.randint(10,size=10)
array([4, 1, 4, 3, 8, 2, 8, 5, 8, 9])

>>> np.random.random_integers(5)
4

>>> arr = np.arange(10)
>>> np.random.shuffle(arr)
>>> arr
[1 7 5 2 9 4 3 6 0 8]
>>>> np.random.permutation(10)
array([1, 7, 4, 3, 0, 9, 2, 5, 8, 6])