C++二分查找(折半查找)算法实例详解

int binary_search(int arr[], int len, int elem)
{
  int low = 0;
  int high = len - 1;
  while (low <= high)
  {
    int mid = (low + high) / 2;
    if (elem == arr[mid]){   //相等，返回mid
      return mid;
    }
    else if (elem > arr[mid]){
      low = mid + 1;  //元素比区间中间元素大，取区间中间元素的下一个元素作为新区间起始位置
    }
    else{
      high = mid - 1; //元素比区间中间元素小，取区间中间元素的上一个元素作为新区间结束位置
    }
  }
  return -1;
}

#include <iostream>
using namespace std;
int binary_search(int arr[], int len, int elem)
{
  int low = 0;
  int high = len - 1;
  while (low <= high)
  {
    int mid = (low + high) / 2;
    if (elem == arr[mid]){
      return mid;
    }
    else if (elem > arr[mid]){
      low = mid + 1;
    }
    else{
      high = mid - 1;
    }
  }
  return -1;
}
//检测是否排好序
int is_sorted(int arr[], int len)
{
  int sorted = 1;
  for (int i = 0; i < len - 1; i++)
  {
    sorted = sorted && arr[i] <= arr[i + 1];
  }
  return sorted;
}
int main()
{
  int arr[] = { 1, 3, 5, 7, 9, 11, 12, 15, 18, 23, 25, 26 };
  int len = sizeof(arr) / sizeof(int);
  int pos;
  int sorted = is_sorted(arr, len);
  if (sorted)
  {
    pos = binary_search(arr, len, 26);
    cout << "pos = " << pos << endl;
  }
  system("pause");
}

pos = 11
请按任意键继续. . .