合并有序数组的实现（java与C语言）

public class Merge {

  //合并有序数组
  public static void mergeSort(int a[], int b[], int c[]) {
    int n = a.length, m = b.length;
    int i, j, k;
    i = j = k = 0;

    while (i < n && j < m) {
      if (a[i] < b[j]) {
        c[k++] = a[i++];
      } else {
        c[k++] = b[j++];
      }

    }
    while (i < n)
      c[k++] = a[i++];
    while (j < m)
      c[k++] = b[j++];
  }

  //打印数组中的元素
  public static void printArr(int a[]) {
    for (int i = 0; i < a.length; i++) {
      System.out.print(a[i] + "\t");
    }
  }

  public static void main(String[] args) {
    System.out.println("Hello World!");
    int[] a = new int[] { 1, 2, 5, 6 };
    int[] b = new int[] { 3, 8, 9, 10 };
    int c[] = new int[8];

    mergeSort(a, b, c);
    printArr(c);
  }
}

1  2  3  5  6  8  9  10

#include <stdio.h>
// 打印数组a
void printArr(int a[],int n){
  for (int i = 0; i < n; ++i)
  {
    printf("%d\t",a[i]);
  }
  printf("\n");
}
//合并有序数组
void mergeArray(int a[],int n,int b[],int m,int c[]){
  int i, j, k; 

  i = j = k = 0; 
  while (i <n && j<m) 
  { 
    if (a[i] < b[j]) 
      c[k++] = a[i++]; 
    else 
      c[k++] = b[j++];  
  } 

  while (i < n) 
    c[k++] = a[i++]; 

  while (j < m) 
    c[k++] = b[j++]; 

}
int main(){
  int a[3]={2,3,6};
  int b[2]={1,5};
  int c[5]={};
  mergeArray(a,3,b,2,c);
  printArr(c,5);
}

yaopans-MacBook-Pro:algorithm yaopan$ ./a.out 
1  2  3  5  6