java计算集合对称差的示例代码

    <dependency>
      <groupId>com.google.guava</groupId>
      <artifactId>guava</artifactId>
      <version>22.0</version>
    </dependency>
    <dependency>
      <groupId>org.apache.commons</groupId>
      <artifactId>commons-collections4</artifactId>
      <version>4.1</version>
    </dependency>

    Set<Integer> a = new HashSet<>(Arrays.asList(1, 2, 3, 4));
    Set<Integer> b = new HashSet<>(Arrays.asList(3, 4, 5, 6));
    Sets.SetView<Integer> result = Sets.symmetricDifference(a,b);
    System.out.println(result);

    Set<Integer> a = new HashSet<>(Arrays.asList(1, 2, 5));
    Set<Integer> b = new HashSet<>(Arrays.asList(1, 2, 3));
    SetUtils.SetView<Integer> result = SetUtils.disjunction(a, b);
    assertTrue(result.toSet().contains(5) && result.toSet().contains(3));

public static <O> Pair<Collection<O>,Collection<O>> disjunction2(final Collection<? extends O> first,
                                  final Collection<? extends O> second,
                                  final Predicate<O> p) {
    final List<O> firstList = first.stream()
        .filter(e -> p.evaluate(e))
        .collect(Collectors.toList());

    final List<O> secondList = second.stream()
        .filter(e -> !firstList.remove(e))
        .collect(Collectors.toList());
    return Pair.of(firstList,secondList);
  }

final List<String> first = Arrays.asList("bbb", "ccc","dddd","aaa");
final List<String> second = Arrays.asList("aaa", "zzz", "ccc");
System.out.println(disjunction(first,second,TruePredicate.truePredicate()));