Java使用分治算法实现排序数索引功能示例【二分搜索】

/**
 * Find the first q and return the index
 * First method is brutal force
 * Second may
 * be Divid and Conquer
 *
 * @author open201
 *
 */
public class Ono {
  /**
   * f(n) = s.length = n;
   *
   * @param s
   * @param q
   * @return
   */
  public static int BrutalForceSearch(int[] s, int q) {
    for (int i = 0; i < s.length; i++) {
      if (q == s[i])
        return i;
    }
    return -1;
  }
  /**
   * f(n) = log(n)
   *
   * @param s
   * @param q
   * @return
   */
  public static int DCSearch(int[] s, int q, int startIndex, int endIndex) {
    if (startIndex > endIndex)
      return -1;
    else {
      int mid = (startIndex + endIndex) / 2;
      if (s[mid] == q)
        return mid;
      else {
        if (s[mid] > q)
          return DCSearch(s, q, startIndex,mid-1);
        else
          return DCSearch(s, q, mid+ 1,endIndex);
      }
    }
  }
  public static void main(String[] args) {
    int [] s = new int[10000000];
    for(int i = 0;i<10000000;i++){
      s[i] = i;
    }
    int q = 10000000-1;
    long startTime = System.currentTimeMillis();
    System.out.println(BrutalForceSearch(s, q));
    long endTime = System.currentTimeMillis();
    System.out.println(endTime-startTime);
    startTime = System.currentTimeMillis();
    System.out.println(DCSearch(s, q, 0, s.length - 1));
    endTime = System.currentTimeMillis();
    System.out.println(endTime-startTime);
  }
}