Android编程实现popupwindow定时消失的方法

// 创建弹出窗口
  popupMenu = new PopupWindow(view, sourceView.getWidth() * 2,
      LayoutParams.WRAP_CONTENT + 200);
  ColorDrawable cd = new ColorDrawable(R.color.white);
  popupMenu.setBackgroundDrawable(cd);
  popupMenu.update();
  popupMenu.setInputMethodMode(PopupWindow.INPUT_METHOD_NEEDED);
  popupMenu.setTouchable(true); // 设置popupwindow可点击
  popupMenu.setOutsideTouchable(true); // 设置popupwindow外部可点击
  popupMenu.setFocusable(true); // 获取焦点
  ColorDrawable dw = new ColorDrawable(0x00);
  popupMenu.setBackgroundDrawable(dw);
  popupMenu.setTouchInterceptor(new View.OnTouchListener() {
    @Override
    public boolean onTouch(View v, MotionEvent event) {
      if (event.getAction() == MotionEvent.ACTION_OUTSIDE) {
        popupMenu.dismiss();
        return true;
      }
      timer.start();
      return false;
    }
  });
}
CountDownTimer timer = new CountDownTimer(3000, 10) {
  @Override
  public void onTick(long millisUntilFinished) {
  }
  @Override
  public void onFinish() {
    popupMenu.dismiss();
  }
};
@Override
public PopupWindow createPupupWindow() {
  return popupMenu;
}
@Override
public void showPopupMenu() {
  if (popupMenu != null && popupMenu.isShowing()) {
    popupMenu.dismiss();
  } else {
    popupMenu.showAsDropDown(sourceView, -sourceView.getWidth() / 2, 0);
    timer.start();
  }
}