Java并发之串行线程池实例解析

import java.util.ArrayDeque;
import java.util.concurrent.BlockingQueue;
import java.util.concurrent.LinkedBlockingDeque;
import java.util.concurrent.ThreadFactory;
import java.util.concurrent.ThreadPoolExecutor;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.atomic.AtomicInteger;

/**
 * Created by wzy on 16-1-5.
 */
public class SerialExecutor {
  private Runnable mActive;
  private ArrayDeque<Runnable> mArrayDeque = new ArrayDeque<>();

  private static final int CPU_COUNT = Runtime.getRuntime().availableProcessors();
  private static final int CORE_POOL_SIZE = CPU_COUNT + 1;
  private static final int MAXIMUM_POOL_SIZE = CPU_COUNT * 2 + 1;
  private static final int KEEP_ALIVE = 1;
  private static final BlockingQueue<Runnable> sPoolWorkQueue =
      new LinkedBlockingDeque<>(128);
  private static final ThreadFactory sThreadFactory = new ThreadFactory() {
    private final AtomicInteger mCount = new AtomicInteger(1);
    @Override
    public Thread newThread(Runnable r) {
      return new Thread(r, "Serial thread #" + mCount.getAndIncrement());
    }
  };
  private static final ThreadPoolExecutor THREAD_EXECUTOR = new ThreadPoolExecutor(CORE_POOL_SIZE,
      MAXIMUM_POOL_SIZE, KEEP_ALIVE, TimeUnit.SECONDS, sPoolWorkQueue, sThreadFactory);

  public synchronized void execute(final Runnable r) {
    mArrayDeque.offer(new Runnable() {
      @Override
      public void run() {
        try {
          r.run();
        } finally {
          scheduleNext();
        }
      }
    });
    // 第一次入队列时mActivie为空，因此需要手动调用scheduleNext方法
    if (mActive == null) {
      scheduleNext();
    }
  }

  private void scheduleNext() {
    if ((mActive = mArrayDeque.poll()) != null) {
      THREAD_EXECUTOR.execute(mActive);
    }
  }

  public static void main(String[] args) {
    SerialExecutor serialExecutor = new SerialExecutor();
    for (int i = 0; i < 10; i ++) {
      final int j = i;
      serialExecutor.execute(new Runnable() {
        @Override
        public void run() {
          System.out.println("The num is :" + (j + 1));
          try {
            Thread.sleep(1000);
          } catch (InterruptedException e) {
            e.printStackTrace();
          }
        }
      });
    }
  }
}