C++找出字符串中出现最多的字符和次数,时间复杂度小于O(n^2)

/********************************************************
Copyright (C), 2016-2017,
FileName: main9
Author: woniu201
Description:求字符串中出现次数最多的字符和次数
********************************************************/
#include "stdafx.h"
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void search(char* pData, int len)
{
 char counts[1024] = {0}; //存放原始数据作为为索引出现的次数
 char bufMax[1024] = {0}; //用于存放出现次数最多的字符
 int max = 0;  //出现次数最多的字符
 for (int i=0; i<len; i++)
 {
 counts[pData[i]] ++;
 }
 for (int i=0; i<1024; i++)
 {
 if (counts[i] > max)
 {
 max = counts[i];
 bufMax[0] = i;
 }else if ((counts[i] == max) && (counts[i] !=0))
 {
 bufMax[strlen(bufMax)] = i;
 }
 }
 printf("出现最多的字符分别为：");
 for (int i=0; i<strlen(bufMax); i++)
 {
 printf("%c ", bufMax[i]);
 }
 printf("\n");
 printf("出现最多的字符的次数：%d\n", max);
}
int main()
{
 char* srcData = "aabbbcddddeeffffghijklmnopqrst";
 search(srcData, strlen(srcData));
 getchar();
 return 1;
}