Python实现查找最小的k个数示例【两种解法】

# -*- coding:utf-8 -*-
class Solution:
  def PartitionOfK(self, numbers, start, end, k):
    if k < 0 or numbers == [] or start < 0 or end >= len(numbers) or k > end:
      return
    low, high = start, end
    key = numbers[low]
    while low < high:
      while low < high and numbers[high] >= key:
        high -= 1
      numbers[low] = numbers[high]
      while low < high and numbers[low] <= key:
        low += 1
      numbers[high] = numbers[low]
    numbers[low] = key
    if low < k:
      self.PartitionOfK(numbers, start + 1, end, k)
    elif low > k:
      self.PartitionOfK(numbers, start, end - 1, k)
  def GetLeastNumbers_Solution(self, tinput, k):
    # write code here
    if k <= 0 or tinput == [] or k > len(tinput):
      return []
    self.PartitionOfK(tinput, 0, len(tinput) - 1, k)
    return sorted(tinput[0:k])
#测试：
sol = Solution()
listNum = [4,5,1,6,2,7,3,8]
rel = sol.GetLeastNumbers_Solution(listNum, 4)
print(rel)

# -*- coding:utf-8 -*-
class Solution:
  def GetLeastNumbers_Solution(self, tinput, k):
    # write code here
    if tinput == [] or k <= 0 or k > len(tinput):
      return []
    result = []
    for num in tinput:
      if len(result) < k:
        result.append(num)
      else:
        if num < max(result):
          result[result.index(max(result))] = num
    return sorted(result)
#测试：
sol = Solution()
listNum = [4,5,1,6,2,7,3,8]
rel = sol.GetLeastNumbers_Solution(listNum, 4)
print(rel)