C++实现哈夫曼树的方法

struct Node {
 char C;
 long key;
 Node *Left, *Right,*parent;
 Node() { Left = Right = NULL; }
};

struct RootA {
 Node *NodeA;
 const int Size;
 int n;
 RootA(int Size) :Size(Size) { n = 0; NodeA = new Node[Size]; }
 ~RootA() { delete[]NodeA; }
};

RootA RA(4);
 //1.在RA.NodeA中存入字母和权值
 for (RA.n = 0;RA.n < RA.Size;RA.n++) {
 cout << "字母：";
 cin >> RA.NodeA[RA.n].C;
 cout << "权值：";
 cin >> RA.NodeA[RA.n].key;
 }

void Sort(RootA *ra) {
 for (int i = 0;i < ra->n;i++) {
 bool ESC = false;
 for (int j = 0;j < ra->n - i - 1;j++) {
  if (ra->NodeA[j].key > ra->NodeA[j + 1].key) {
  Node T;T = ra->NodeA[j];ra->NodeA[j] = ra->NodeA[j + 1];ra->NodeA[j + 1] = T;
  ESC = true;
  }
 }
 if (!ESC) return;
 }
}

while (RA.n > 1) {
 //1.将RA.NodeA[0]和RA.NodeA[1]合并，将其余向前移动
 Node *NewNode0 = new Node;
 *NewNode0 = RA.NodeA[0];
 Node *NewNode1 = new Node;
 *NewNode1 = RA.NodeA[1];
 RA.NodeA[0].C = ' ';
 RA.NodeA[0].key = RA.NodeA[0].key + RA.NodeA[1].key;
 RA.NodeA[0].Left = NewNode0;
 NewNode0->parent = &RA.NodeA[0];
 RA.NodeA[0].Right = NewNode1;
 NewNode1->parent = &RA.NodeA[0];
 for (int i = 1;i < RA.n-1;i++) {
  RA.NodeA[i] = RA.NodeA[i + 1];
 }
 RA.n = RA.n - 1;
 //2.排序
 Sort(&RA);
 }

void CrateCode(Node *t,string &s) {
 //1.遍历节点，遍历左节点编码为0,右节点则为1，递归，直到输出所有叶子节
 if (t->Left != NULL && t->Right != NULL) {
 s.push_back('0'); CrateCode(t->Left, s);
 s.pop_back();
 s.push_back('1');CrateCode(t->Right, s);
 s.pop_back();
 }
 else {
 cout << "哈夫曼编码：";
 cout << t->C << ":" << s<<endl;
 }
}