使用Java 8 Lambda表达式将实体映射到DTO的操作

public class ActiveUserListDTO { 
  public ActiveUserListDTO() {
  }
 
  public ActiveUserListDTO(UserEntity userEntity) { 
    this.username = userEntity.getUsername(); 
   ...
  }
}

userRepository.findAll();
Problem:
Find.All() method signature (like many others) returns java.lang.Iterable<T>
java.lang.Iterable<T> findAll(java.lang.Iterable<ID> iterable)

**
 * List -> Map
 * 需要注意的是：
 * toMap 如果集合对象有重复的key，会报错Duplicate key ....
 * apple1,apple12的id都为1。
 * 可以用 (k1,k2)->k1 来设置，如果有重复的key,则保留key1,舍弃key2
 */
Map<Integer, Apple> appleMap = appleList.stream().collect(Collectors.toMap(Apple::getId, a -> a,(k1,k2)->k1));
 
安照某一字段去重
list = list.stream().filter(distinctByKey(p -> ((ModCreditColumn) p).getFieldCode())).collect(Collectors.toList());
 
List<Double> unitNetValue = listIncreaseDto.stream().map(IncreaseDto :: getUnitNetValue).collect(Collectors.toList());
 
//求和 对象List
BigDecimal allFullMarketPrice = entityList.stream().filter(value -> value.getFullMarketPrice()!= null).map(SceneAnalysisRespVo::getFullMarketPrice).reduce(BigDecimal.ZERO, BigDecimal::add);
 
 List<BigDecimal> naturalDayList;
 BigDecimal total = naturalDayList.stream().reduce(BigDecimal.ZERO, BigDecimal::add);
 
分组函数
Map<String, List<SceneAnalysisRespVo>> groupMap = total.getGroupList().stream().collect(Collectors.groupingBy(SceneAnalysisRespVo::getVmName));
 
//DV01之和
BigDecimal allDV01 = values.stream().filter(sceneAnalysisRespVo -> sceneAnalysisRespVo.getDv() != null).map(SceneAnalysisRespVo::getDv).reduce(BigDecimal.ZERO, BigDecimal::add);