C++ 实现输入含空格的字符串

int main() 
{
 char st[50];
 scanf("%[^\n]",st);// \n作为字符串输入的结束符
 printf("%s",st);
 return 0;
}

int main() 
{ 
 string st; 
 getline(cin,st); 
 cout<<st<<endl;
 return0; 
}

int main() 
{ 
 char st[50]; 
 cin.get(st,50); 
 cout<<a<<endl;// 输出也可以用printf("%s",st); 
 return0; 
}

int main() 
{ 
 char st[50]; 
 cin.getline(a,50); 
 cout<<a<<endl; // 输出也可以用printf("%s",st); 
 return0; 
}

（a）c_str() 
 char p[50]; 
 string str="I Love Ningbo!"; 
 strcpy(p,str.c_str()); 
 printf("%s",p);
 
（b）data()
 char p[50]; 
 string str="I Love Ningbo!"; 
 strcpy(p,str.data()); 
 printf("%s",p);

#include<iostream>
using namespace std;
int main()
{
 cin >> noskipws;//设置cin读取空白符；
 char c;
 size_t acount =0, ecount =0, icount =0, ocount =0, ucount = 0,scount = 0;
 while (cin >> c)
 {
 if (c == 'a')++acount;
 if (c == 'e')++ecount;
 if (c == 'i')++icount;
 if (c == 'o')++ocount;
 if (c == 'u')++ucount;
 if (c == ' ')++scount;
 }
 cout << "a: " << acount << endl;
 cout << "e: " << ecount << endl;
 cout << "i: " << icount << endl;
 cout << "o: " << ocount << endl;
 cout << "u: " << ucount << endl;
 cout << "space: " << scount << endl;
 return 0;
}