使用Swagger直接上传文件的方法

[Consumes("multipart/form-data")]
[ODataRoute]
[HttpPost]
public async Task<ActionResult> Post(IFormCollection collection)
{
 var file = collection.Files[0];
 if(file != null)
 {
 var filename = DateTime.Now.ToString("yyyyMMddHHmmss") + file.FileName;
 var path = Path.Combine(_webHostEnvironment.WebRootPath, "Files", filename);
 using FileStream fileStream = new FileStream(path, FileMode.Create);
 await file.CopyToAsync(fileStream);
 var uri = "Files/" + filename;
 var fileEntity = new Models.File { Url = uri, LastModified = DateTime.Now };
 _homeworkDataContext.Files.Add(fileEntity);
 await _homeworkDataContext.SaveChangesAsync();
 return Created(WebUtility.UrlEncode(uri), fileEntity);
 }
 return BadRequest();
}

// CODE FROM https://www.talkingdotnet.com/how-to-upload-file-via-swagger-in-asp-net-core-web-api/
public class FileUploadOperation : IOperationFilter
{
 public void Apply(Operation operation, OperationFilterContext context)
 {
 if (operation.OperationId.ToLower() == "apivaluesuploadpost")
 {
  operation.Parameters.Clear();
  operation.Parameters.Add(new NonBodyParameter
  {
  Name = "uploadedFile",
  In = "formData",
  Description = "Upload File",
  Required = true,
  Type = "file"
  });
  operation.Consumes.Add("multipart/form-data");
 }
 }
}

options.OperationFilter<FileUploadOperation>(); 

requestBody:
 content:
 multipart/form-data:
 schema:
 type: object
 properties:
  fileName:
  type: string
  format: binary

public class FileUploadOperation : IOperationFilter
{
 public void Apply(OpenApiOperation operation, OperationFilterContext context)
 {
 //判断上传文件的类型，只有上传的类型是IFormCollection的才进行重写。
 if (context.ApiDescription.ActionDescriptor.Parameters.Any(w => w.ParameterType == typeof(IFormCollection)))
 {
  Dictionary<string, OpenApiSchema> schema = new Dictionary<string, OpenApiSchema>();
  schema["fileName"] = new OpenApiSchema { Description = "Select file", Type = "string", Format = "binary" };
  Dictionary<string, OpenApiMediaType> content = new Dictionary<string, OpenApiMediaType>();
  content["multipart/form-data"] = new OpenApiMediaType { Schema = new OpenApiSchema { Type = "object", Properties = schema } };
  operation.RequestBody = new OpenApiRequestBody() { Content = content };
 }
 }
}