Unity报错InvalidOperationException: out of sync的解决

public void ShowMyCard(int[] card)
    {
        if (myCardsDic.Count > 0)
        {
            foreach (int k in myCardsDic.Keys)
            {
       if(满足一个条件)
                   {
                        //删除或者修改此元素
            //myCardsDic.Remove(k);
          }
            }
        }
    }

    public void ShowMyCard(int[] card)
    {
        if (myCardsDic.Count > 0)
        {
            List<int> myCardsList = new List<int>();
            foreach (int k in myCardsDic.Keys)
            {
                if(满足一个条件)
                   {
                        //保存这个元素
                     myCardsList.Add(myCardsDic[k]);
                }
            }
           foreach (int item in myCardsList)
            {
       //做你要做的事情
            }
        }
    }

    public IEnumerator ShowMyCard(int[] card)
    {
        if (myCardsDic.Count > 0)
        {
            foreach (int k in myCardsDic.Keys)
            {
                float x = myCardsDic[k].localScale.x;
                myCardsDic[k].DOScaleX(0, 0.02f).OnComplete(() =>
                {
                     myCardsDic[k].DOScaleX(x, 0.02f);
                });
                yield return new WaitForFixedUpdate();
            }
        }
    }

    public void ShowMyCard(int[] card)
    {
        if (myCardsDic.Count > 0)
        {
            foreach (int k in myCardsDic.Keys)
            {
                float x = myCardsDic[k].localScale.x;
                myCardsDic[k].DOScaleX(0, 0.02f).OnComplete(() =>
                {
                     myCardsDic[k].DOScaleX(x, 0.02f);
                });
            }
        }
    }