c语言实现两个值互相交换的函数

#include <stdio.h>

void swap(int n1, int n2)
{
    int tmp;
    tmp = n1;
    n1 = n2;
    n2 = tmp;
}

int main(void)
{
    int a, b;
    puts("please input two integers.");
    printf("a = "); scanf("%d", &a);
    printf("b = "); scanf("%d", &b);
    
    swap(a, b);  //a、b作为实参传递给n1和n2，n1和n2实现了互换，但是值传递是单向的，n1和n2的值并不能返回到实参a、b中，因此a，b还是原来的值 
    
    printf("swapped a = %d\n", a);
    printf("swapped b = %d\n", b);
    
    return 0;
}

#include <stdio.h>

void swap2(int *n1, int *n2)
{
    int tmp;
    tmp = *n1;
    *n1 = *n2;
    *n2 = tmp;    
} 

int main(void)
{
    int a, b;
    puts("please input two integers.");
    printf("a = "); scanf("%d", &a);
    printf("b = "); scanf("%d", &b);
    
    swap2(&a, &b); //将a和b的指针作为实参传递给指针变量n1和n2，n1和n2称为指向a和b的指针，*n1和*n2分别为a和b的别名，对*n1和n2进行修改，就相当于对a和b进行修改 
    
    printf("\nswapped a = %d\n",a);
    printf("swapped b = %d\n", b);
    
    return 0;
}

int t;
t=x;
x=y;
y=t;

void swap(int x, int y)
{
       int t;
       t=x;
       x=y;
       y=t;
}

void swap(int &x, int &y)
{
       int t;
       t=x;
       x=y;
       y=t;
}

#include<stdio.h>
void swap(int *x, int *y)
{
 int t;
    t=*x;
 *x=*y;
 *y=t;
}
int main()
{
 int a=1,b=2;
 swap(&a,&b);
 printf("a=%d,b=%d",a,b);
 return 0;
}