没有编辑器的环境下是如何创建Servlet(Tomcat+Java)项目的?

classpath

WEB-INF
index.html

#classes为java程序文件
classes
#web.xml为映射文件
web.xml

import javax.servlet.*;
import java.io.IOException;
public class ServletDome01 implements Servlet {
	public void init(ServletConfig servletConfig) throws ServletException {
    }    
    public ServletConfig getServletConfig() {
        return null;
    }
   public void service(ServletRequest servletRequest, ServletResponse servletResponse) throws ServletException, IOException {
  
        System.out.println("servlet");
    }   
    public String getServletInfo() {
        return null;
    }   
    public void destroy() {
    }
}

javac ServletDome01.java

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
         version="4.0">

    <servlet>
        <!--自定义，一般为类名-->
        <servlet-name>ServletDome01</servlet-name>
        <!--一定是+ .类名-->
        <servlet-class>ServletDome01</servlet-class>
    </servlet>
    <!--给Servlet提供（映射)一个可供客户端访问的URI-->
    <servlet-mapping>
        <!--和servlet中的name必须相同-->
        <servlet-name>ServletDome01</servlet-name>
        <!-- servlet的映射路径 -->
        <url-pattern>/ServletDome01</url-pattern>
    </servlet-mapping>

</web-app>