Java 如何从list中删除符合条件的数据

import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
public class Main {
    public static void main(String[] args) {
        ArrayList<String> strs = new ArrayList<>();
        strs.add("1");
        strs.add("32");
        strs.add("3");
        strs.add("4");
        strs.add("5");
        strs.add("36");
//        remove1(strs);
//        remove2(strs);
//        remove3(strs);
        remove4(strs);
        System.out.println("after");
        printList(strs);
    }
    //使用iterator，这个是java和Android源码中经常使用到的一种方法，所以最为推荐
    public static void remove1(List<String> list) {
        Iterator<String> sListIterator = list.iterator();
        while (sListIterator.hasNext()) {
            String str = sListIterator.next();
            if (str.contains("3")) {
                sListIterator.remove();
            }
        }
    }
    //倒序删除，以防因为删除中间项导致数据下标变更，使得数据出错
    public static void remove2(List<String> list) {
        for (int i = list.size() - 1; i >= 0; i--) {
            if (list.get(i).contains("3")) {
                list.remove(i);
            }
        }
    }
    // 顺序删除，但是对下标和索引进行了处理
    public static void remove3(List<String> list) {
        for (int i = 0, len = list.size(); i < len; i++) {
            if (list.get(i).contains("3")) {
                list.remove(i);
                len--;
                i--;
            }
        }
    }
    // 在遍历过程中不直接操作原list
    public static void remove4(List<String> list) {
        List<String> temp = new ArrayList<>();
        for (String str : list) {
            if (str.contains("3")) {
                temp.add(str);
            }
        }
        list.removeAll(temp);
    }
    public static void printList(List<String> list) {
        for (String str : list) {
            System.out.println(str);
        }
    }
}

  List<UserFictitious> list = new ArrayList<>();
        for (int i = 0; i < 50; i++){
            UserFictitious userFictitious = new UserFictitious();
            userFictitious.setUserFictitiousName(String.valueOf(i));
            list.add(userFictitious);
        }
  list.removeIf(item -> item.getUserFictitiousName().equals("1"));
  System.out.println(list);

  default boolean removeIf(Predicate<? super E> filter) {
        Objects.requireNonNull(filter);
        boolean removed = false;
        final Iterator<E> each = iterator();
        while (each.hasNext()) {
            if (filter.test(each.next())) {
                each.remove();
                removed = true;
            }
        }
        return removed;
    }