c++实现超简单的贪吃蛇游戏实例介绍

#include<bits/stdc++.h>
#include<windows.h>
#include<iostream>
#include<conio.h>
int main() {
    int headx = 0, heady = 0, len = 5, map[1600] = { 0 }, i = 0;
    char c = 'd', cl = 'd',body=3,head=2;
    /*随机数生成*/
    srand((unsigned)time(0));
    system("mode con:cols=80 lines=40");
    map[rand() % 1600] = -1;
    while (true)
    {
        if (_kbhit())//判断键盘输入
        {
            cl =_getch();
            if (cl < 97) cl += 32;
            if (cl == 'a' && c != 'd' || cl == 'd' && c != 'a' ||cl == 'w' && c != 's' || cl == 's' && c != 'w')//判断输入方向是否与原方向冲突
                c = cl;
        }
        /*改变蛇头坐标*/
        if (c == 'a') headx--;
        if (c == 'd') headx++;
        if (c == 'w') heady--;
        if (c == 's') heady++;
        /*判断蛇头是否撞墙*/
        if(headx==-1||headx==40||heady==-1||heady==40)
            break;
        /*判断蛇头是否为空地*/
        if (map[heady * 40 + headx])
        {
            if (map[heady * 40+headx] > 0) break;
            /*吃到食物，蛇身+1，并在空地生成新的食物*/
            if (map[heady * 40 + headx] < 0)
            {
                len++;
                for (i = rand() % 1600; map[i] || !(map[i] = -1); i = rand() % 1600);
            }
        }
        /*是空地则蛇身值整体减1，蛇尾由1减为0变成空地*/
        else for (i = 0; i < 1600; i++)
        {
            if (map[i] > 0) map[i] -= 1;
        }
        system("cls");
        /*新蛇头赋值，遍历map，值大于0为蛇身，等于0为空地，小于0为食物*/
        for (map[heady * 40 + headx] = len, i = 0; i < 1600; i++)
        {
            if (map[i] == len) {
                printf("%2d", map[i]);
                continue;
            }
            if (map[i] > 0)  printf("%2d", map[i]);
            if (map[i] == 0)  printf("%2d", map[i]);
            if (map[i] == -1) printf("%2d", map[i]);//打印
         }
        Sleep(100);
    }
}