C++如何切割String对象的方法

size_type find(const basic_string &str,size_type pos=0)

string substr(size_type pos=0,size_type count=npos)

int i=42;
string s=to_string(i);

string str='42';
stoi(str);

nums = [3,2,4], target = 6

#include<iostream>
#include<vector>
#include<string>
using namespace std;

void spiltStr(string str,const string & split,vector<string>&strlist)
{
    strlist.clear();
    if(str=="")
        return;
    string strs=str+split;
    size_t pos=strs.find(split);
    int steps=split.size();

    while(pos!=strs.npos)
    {
        //substr 复制字符串，起始位置，复制字符数目
        string temp=strs.substr(0,pos);
        strlist.push_back(temp);
        strs=strs.substr(pos+steps,strs.size());
        pos=strs.find(split);
    }

}

int main()
{
    vector<int>num;
    vector<string>strlist;
    string inputStr;
    string tempStr;
    int target;

    getline(cin,inputStr);
    if(inputStr=="")
    {
        return 0;
    }

    //分割输入的字符串
    spiltStr(inputStr,"[",strlist);
    spiltStr(strlist[1],"]",strlist);
    spiltStr(strlist[0],",",strlist);

    //将vector<string>spiltStr的数值写入vector<int>nums中
    for(auto i:strlist)
    {
        num.push_back(stoi(i));
    }

    spiltStr(inputStr,"=",strlist);

    // spiltStr(strlist.back(),"=",strlist);
    target=stoi(strlist.back());


    for(auto i:num)
    {
        cout<<i<<" ";
    }
    cout<<endl;
    cout<<target<<endl;
    

}