C++深入分析回顾函数重载

#include <stdio.h>
class Test
{
    int i;
public:
    Test()
    {
        printf("Test::Test()\n");
        this->i = 0;
    }
    Test(int i)
    {
        printf("Test::Test(int i)\n");
        this->i = i;
    }
    Test(const Test& obj)
    {
        printf("Test(const Test& obj)\n");
        this->i = obj.i;
    }
    static void func()
    {
        printf("void Test::func()\n");
    }
    void func(int i)
    {
        printf("void Test::func(int i), i = %d\n", i);
    }
    int getI()
    {
        return i;
    }
};
void func()
{
    printf("void func()\n");
}
void func(int i)
{
    printf("void func(int i), i = %d\n", i);
}
int main()
{
    func();
    func(1);
    Test t;        // 初始化，调用没有参数的构造函数Test()，输出Test::Test()
    Test t1(1);    // Test::Test(int i)
    Test t2(t1);   // Test(const Test& obj)
    func();        // void func()
    Test::func();  // void Test::func()
    func(2);       // void func(int i), i = 2;
    t1.func(2);    // void Test::func(int i), i = 2
    t1.func();     // void Test::func()
    return 0;
}

#include <stdio.h>
#include <string.h>
char* strcpy(char* buf, const char* str, unsigned int n)
{
    return strncpy(buf, str, n);
}
int main()
{
    const char* s = "AutumnZe";
    char buf[8] = {0};
    //strcpy(buf, s);
    strcpy(buf, s, sizeof(buf)-1);
    printf("%s\n", buf);
    return 0;
}