使用Java判定一个数值是否在指定的开闭区间范围内

/**
 * 开闭区间正则表达式
 */
private static final Pattern NUM_RANGE_PATTERN = Pattern.compile("[\\[|\\(]\\s?\\d+\\s?,\\s?\\d+\\s?[\\)|\\]]");

/**
 * 左半区间正则表达式
 */
private static final Pattern LEFT_NUM_RANGE_PATTERN = Pattern.compile("[\\[|\\(]\\s?\\d+\\s?,\\s?[\\)|\\]]");

/**
 * 右半区间正则表达式
 */
private static final Pattern RIGHT_NUM_RANGE_PATTERN = Pattern.compile("[\\[|\\(],\\s?\\d+\\s?[\\)|\\]]");

/**
 * 判断是否为有效的数字区间范围
 * @param numRange 数字区间
 * @return boolean
 */
public static boolean isValidNumRange(String numRange) {
    return NUM_RANGE_PATTERN.matcher(numRange).matches()
            || LEFT_NUM_RANGE_PATTERN.matcher(numRange).matches()
            || RIGHT_NUM_RANGE_PATTERN.matcher(numRange).matches();
}

/**
 * 判断数值是否在区间范围内
 * @param number 数值
 * @param numRange 开闭区间
 * @return boolean
 */
public static boolean inNumRange(int number, String numRange) {
    Objects.requireNonNull(numRange);

    if (!isValidNumRange(numRange)) {
        return false;
    }

    String[] pairs = numRange.split(",");

    // 获取开闭区间的最小值和最大值
    List<String> rangeNums = Arrays.stream(pairs).map(str -> str.replaceAll("[(|)|\\[|\\]]", "").trim()).collect(Collectors.toList());
    Integer minValue = "".equals(rangeNums.get(0)) ? null : Integer.valueOf(rangeNums.get(0));
    Integer maxValue = "".equals(rangeNums.get(1)) ? null : Integer.valueOf(rangeNums.get(1));

    // 判定数值是否大于最小值
    boolean minMatched = (minValue == null) || (pairs[0].startsWith("[") ? number >= minValue : number > minValue);
    // 判定数值是否小于最大值
    boolean maxMatched = (maxValue == null) || (pairs[1].endsWith("]") ? number <= maxValue : number < maxValue);

    return minMatched && maxMatched;
}

public static void main(String[] args) {
        System.out.println(inNumRange(1, "(0, 2]"));
        System.out.println(inNumRange(1, "(, 2]"));
        System.out.println(inNumRange(1, "(1, 4]"));
        System.out.println(inNumRange(1, "(0, ]"));
    }