C#模拟MSN窗体抖动的实现代码

//第一种抖动
private void button1_Click(object sender, EventArgs e)
{
  int recordx = this.Left;      //保存原来窗体的左上角的x坐标
  int recordy = this.Top;       //保存原来窗体的左上角的y坐标

  Random random = new Random();   

  for (int i = 0; i < 100; i++)
  {
 int x = random.Next(rand);
 int y = random.Next(rand);
 if (x % 2 == 0)
 {
   this.Left = this.Left + x;
 }
 else
 {
   this.Left = this.Left - x;
 }
 if (y % 2 == 0)
 {
   this.Top = this.Top + y;
 }
 else
 {
   this.Top = this.Top - y;
 }

 this.Left = recordx;      //还原原始窗体的左上角的x坐标
 this.Top = recordy;       //还原原始窗体的左上角的y坐标
  }
  
}


//第二种抖动
private void button2_Click(object sender, EventArgs e)
{
  int recordx = this.Left;
  int recordy = this.Top;
  Random random = new Random();
  for (int i = 0; i < 50; i++)
  {
 int x = random.Next(rand);
 int y = random.Next(rand);
 if (x % 2 == 0)
 {
   this.Left = this.Left + x;
 }
 else
 {
   this.Left = this.Left - x;
 }
 if (y % 2 == 0)
 {
   this.Top = this.Top + y;
 }
 else
 {
   this.Top = this.Top - y;
 }
 System.Threading.Thread.Sleep(1);
  }
  this.Left = recordx;
  this.Top = recordy;
}