用VC++6.0实现石头剪刀布游戏的程序

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>
int exist_in(char *arr1[][2], char *arr2[], int length);//胜负判断函数
void nextround (void);//本轮结束后的处理轮函数
enum {QUIT,OK} status;//标志位，QUIT=0,OK=1
int vcnt = 0,dcnt = 0,tcnt = 0;//数据统计
int main(void)
{
    int i = 0, length;
    time_t t;
    status = OK;
    char *person = (char *) malloc(100);//动态内存分配
    char *computer = (char *) malloc(100);
    char *computer_person[2];
    char *guess_arr[] = {"石头", "剪刀", "布"};
    char *win[3][2] = {{"布", "石头"}, {"石头", "剪刀"}, {"剪刀", "布"}};   
    length = (int)sizeof(win)/(int)sizeof(win[0]);//此例中length=3
    while (status == OK)//标志位1,执行死循环
    {
        srand((unsigned) time(&t));
        i = rand() % 3 ;//srand和rand配合产生随机数
        computer = guess_arr[i];//将随机数转换为石头剪刀或者布的字符串
        computer_person[0] = computer;//将计算机的出拳结果放入*computer_person
        do{
            printf("请输入 剪刀 石头 布:\n");
            scanf("%s",person);
            if (strcmp(person,"god") == 0)//上帝模式，实现可看到电脑出拳结果
            {
                printf("*********************************\n");
                printf("上帝你好，电脑本局的出的是 : %s \n",computer);
                printf("*********************************\n");
                continue;
            }
            else
                printf("你输入的是:%s\n", person);//下一行用于判断用户的输入是否为石头剪刀布
                if ((strcmp(person,"石头") == 0 )||(strcmp(person,"剪刀") == 0 )||(strcmp(person,"布") == 0 ))
                    break;//结果为石头剪刀布之一，跳出循环。
                else
                    printf("请检查你的输入是否为石头剪刀或者布： \n");
        }while(1);
        computer_person[1] = person;
        tcnt++;       
        if (strcmp(computer, person) == 0 )
        {
            printf("平手！\n\n");
        }
        else if (exist_in(win, computer_person, length))
        {
              printf("电脑获胜\n\n");
              dcnt++;
        }
        else
        {
            printf("玩家获胜\n\n");
            vcnt++;
            nextround();
        }  
    }
    person = NULL;
    computer = NULL;   
    free(person);
    free(computer);
    return 0;
}
/**********************************************
 exist_in函数用于判断是否是电脑获胜，length为3，比较3次，arr1和arr2中字符串的
 顺序即可判断出电脑是否获胜。
 *********************************************/
int exist_in(char *arr1[][2], char *arr2[], int length)
{
    int i;
    for (i = 0; i < length; i++)
    {
        if (strcmp(arr1[i][0], arr2[0]) == 0 && strcmp(arr1[i][1], arr2[1]) == 0)
        {
            return 1;
        }
    }
    return 0;
 }
void nextround (void)
{
    int m = 0;
    printf("请输入指令：1退出，2继续，3数据总结\n");
    scanf ("%d",&m);
    switch (m)
    {
    case 1:
        status = QUIT;
        break;
    case 2:
        printf("新的一局开始\n");
        break;
    case 3:
        printf("您的胜场数是%d，败场数是%d，总场数是%d\n",vcnt,dcnt,tcnt);
        status = QUIT;
        break;
    default:
        printf("输入错误退出");
        status = QUIT;
        break;
    }
}