AndroidGUI27中findViewById返回null的快速解决办法

<?xml version="1.0"encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
>
<EditText android:id="@+id/et_search"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text=""
/>
<ListView android:id="@+id/lv_contactbook"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
/>
</LinearLayout>

@Override
public void onCreate(BundlesavedInstanceState)
{
super.onCreate(savedInstanceState);
ListViewlv = (ListView)findViewById(R.id.lv_contactbook);
setContentView(R.layout.main);
//…
}

<?xml version="1.0"encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="horizontal"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
> 
<TextView android:id="@+id/tv_contact_id"
android:layout_width="0px"
android:layout_height="0px"
android:visibility="invisible"
android:gravity="center_vertical"
/>
<TextView android:id="@+id/tv_contactname"
android:layout_width="wrap_content"
android:layout_height="36dip"
android:textSize="16dip"
android:layout_marginTop="10dip"
android:textColor="#FFFFFFFF"
/>
</LinearLayout>

View rowview = (View)inflater.inflate(R.layout.rowview, parent, false);
TextView tv_contact_id =(TextView)rowview.findViewById(R.id.tv_contact_id);
TextView tv_contactname =(TextView)rowview.findViewById(R.id.tv_contactname);