正确遍历删除List中的元素方法(推荐)

/**
   * 使用增强的for循环
   * 在循环过程中从List中删除元素以后，继续循环List时会报ConcurrentModificationException
   */
  public void listRemove() {
    List<Student> students = this.getStudents();
    for (Student stu : students) {
      if (stu.getId() == 2) 
        students.remove(stu);
    }
  }

/**
   * 像这种使用增强的for循环对List进行遍历删除，但删除之后马上就跳出的也不会出现异常
   */
  public void listRemoveBreak() {
    List<Student> students = this.getStudents();
    for (Student stu : students) {
      if (stu.getId() == 2) {
        students.remove(stu);
        break;
      }
    }
  }

/**
   * 这种遍历有可能会遗漏某个元素,因为删除元素后List的size在
   * 变化，元素的索引也在变化，比如你循环到第2个元素的时候你把它删了，
   * 接下来你去访问第3个元素，实际上访问到的是原先的第4个元素。当访问的元素
   * 索引超过了当前的List的size后还会出现数组越界的异常，当然这里不会出现这种异常，
   * 因为这里每遍历一次都重新拿了一次当前List的size。
   */
  public void listRemove2() {
    List<Student> students = this.getStudents();
    for (int i=0; i<students.size(); i++) {
      if (students.get(i).getId()%3 == 0) {
        Student student = students.get(i);
        students.remove(student);
      }
    }
  }

/**
   * 使用Iterator的方式也可以顺利删除和遍历
   */
  public void iteratorRemove() {
    List<Student> students = this.getStudents();
    System.out.println(students);
    Iterator<Student> stuIter = students.iterator();
    while (stuIter.hasNext()) {
      Student student = stuIter.next();
      if (student.getId() % 2 == 0)
//这里要使用Iterator的remove方法移除当前对象，如果使用List的remove方法，则同样会出现ConcurrentModificationException
        stuIter.remove();
    }
    System.out.println(students);
  }

import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;

public class ListRemove {

  public static void main(String args[]) {
    ListRemove lr = new ListRemove();
    lr.listRemove();
    lr.listRemoveBreak();
//    lr.listRemove2();
//    lr.iteratorRemove();
  }

  /**
   * 使用增强的for循环
   * 在循环过程中从List中删除元素以后，继续循环List时会报ConcurrentModificationException
   */
  public void listRemove() {
    List<Student> students = this.getStudents();
    for (Student stu : students) {
      if (stu.getId() == 2) 
        students.remove(stu);
    }
  }
  
  /**
   * 像这种使用增强的for循环对List进行遍历删除，但删除之后马上就跳出的也不会出现异常
   */
  public void listRemoveBreak() {
    List<Student> students = this.getStudents();
    for (Student stu : students) {
      if (stu.getId() == 2) {
        students.remove(stu);
        break;
      }
    }
  }
  
  /**
   * 这种不使用增强的for循环，每次重新获取list的size遍历的情况运行时不会报错，但是可能删除的结果是错的。
   */
  public void listRemove2() {
    List<Student> students = this.getStudents();
    for (int i=0; i<students.size(); i++) {
      if (students.get(i).getId()%2 == 0)
        students.remove(i);
    }
  }
  
  /**
   * 使用Iterator的方式也可以顺利删除和遍历
   */
  public void iteratorRemove() {
    List<Student> students = this.getStudents();
    System.out.println(students);
    Iterator<Student> stuIter = students.iterator();
    while (stuIter.hasNext()) {
      Student student = stuIter.next();
      if (student.getId() % 2 == 0)
        stuIter.remove();
    }
    System.out.println(students);
  }
  
  private List<Student> getStudents() {
    List<Student> students = new ArrayList<Student>() {
      {
        int i = 0;
        while (i++ < 10) {
          Student student = new Student(i, "201200" + i, "name_" + i);
          this.add(student);
        }
      }
    };
    return students;
  }
}

public class Student {

  private int id;
  private String stuNo;
  private String name;
  
  public Student() {
    
  }
  
  public Student(int id, String stuNo, String name) {
    this.id = id;
    this.stuNo = stuNo;
    this.name = name;
  }

  public int getId() {
    return id;
  }

  public void setId(int id) {
    this.id = id;
  }

  public String getStuNo() {
    return stuNo;
  }

  public void setStuNo(String stuNo) {
    this.stuNo = stuNo;
  }

  public String getName() {
    return name;
  }

  public void setName(String name) {
    this.name = name;
  }

  @Override
  public String toString() {
    return "Student [id=" + id + ", name=" + name + ", stuNo=" + stuNo
        + "]";
  }
  
}