JS中toFixed(2)精度问题的原因以及解决办法

var b = 1.335

b.toFixed(2)

"1.33"

var b = 1.345

b.toFixed(2)

"1.34"

var b = 1.355

b.toFixed(2)

"1.35"

var b = 1.365

b.toFixed(2)

"1.36"

var b = 1.375

b.toFixed(2)

"1.38"

var b = 1.385

b.toFixed(2)

"1.39"

Number.prototype.toFixed = function (n) {
let result = number.toString();
const arr = result.split('.');
const integer = arr[0];
const decimal = arr[1];
result = integer + '.' + decimal.substr(0, n);
const last = decimal.substr(n, 1);

if (parseInt(last, 10) >= 5) {
const x = Math.pow(10, n);
result = ((parseFloat(result) * x) + 1) / x;
result = result.toFixed(n);
}
return result;
}

console.log(2.115 * 100) // 211.50000000000003
console.log(2.0115 * 1000) // 2011.4999999999998

result = (Math.round((parseFloat(result)) * x) + 1) / x;

// toFixed兼容方法
Number.prototype.toFixed = function (n) {
    if (n > 20 || n < 0) {
        throw new RangeError('toFixed() digits argument must be between 0 and 20');
    }
    const number = this;
    if (isNaN(number) || number >= Math.pow(10, 21)) {
        return number.toString();
    }
    if (typeof (n) == 'undefined' || n == 0) {
        return (Math.round(number)).toString();
    }
    let result = number.toString();
    const arr = result.split('.');
    // 整数的情况
    if (arr.length < 2) {
        result += '.';
        for (let i = 0; i < n; i += 1) {
            result += '0';
        }
        return result;
    }
    const integer = arr[0];
    const decimal = arr[1];
    if (decimal.length == n) {
        return result;
    }
    if (decimal.length < n) {
        for (let i = 0; i < n - decimal.length; i += 1) {
            result += '0';
        }
        return result;
    }
    result = integer + '.' + decimal.substr(0, n);
    const last = decimal.substr(n, 1);
    // 四舍五入，转换为整数再处理，避免浮点数精度的损失
    if (parseInt(last, 10) >= 5) {
        const x = Math.pow(10, n);
        result = (Math.round((parseFloat(result) * x)) + 1) / x;
        result = result.toFixed(n);
    }
    return result;
}