Java中如何将String转JSONObject

@Test
    public void TestJsonObject() {
        String datajson = "" +
                "[" +
                "   {" +
                "       'projectId':'00a8de32-422c-4b8d-b945-d9cda7f30a31'," +
                "       'projectName':'年产片式元器件7.2亿个、高分子固体电容器3.96亿个等项目（标准厂房、连廊A，甲类仓库，办公楼，宿舍，值班门卫，垃圾房）'," +
                "       'iconType':'yc'," +
                "       'eqpType':'yc'," +
                "       'sn':'SZWJJJ8MQX20200403134027'," +
                "       'name':'测试第三方01'," +
                "       'wkt':'测试第三方01'," +
                "       'sn':'POINT(120.698299 31.272362)'" +
                "   }," +
                "   {" +
                "       'projectId':'00a8de32-422c-4b8d-b945-d9cda7f30a31'," +
                "       'projectName':'测试项目编号名称'," +
                "       'iconType':'yc'," +
                "       'eqpType':'yc'," +
                "       'sn':'FDASDFAFDAFYF89AS6F897DD'," +
                "       'name':'扬尘设备001'," +
                "       'wkt':'扬尘设备001'," +
                "       'sn':'POINT(120.698299 31.272362)'" +
                "   }" +
                "]";
        JSONArray jsonArray = JSONArray.parseArray(datajson);
        for(int i=0; i<jsonArray.size(); i++) {
            JSONObject object = jsonArray.getJSONObject(i);
            SmartProejctEquipmentMap myclass = JSONObject.parseObject(object.toJSONString() , SmartProejctEquipmentMap.class);// 将string类型直接封装成对象
            System.out.println(myclass.toString());
        }