SpringBoot读取resource目录下文件失败的原因及解决方案

// 读取resource目下脚本模板文件
String templatePath = "/script/test.py";
ClassPathResource resource = new ClassPathResource(templatePath);
File file;
try {
    file = resource.getFile();
} catch (IOException e) {
    e.printStackTrace();
}

// 读取resource目下脚本模板文件
String templatePath = "/script/test.py";
ClassPathResource resource = new ClassPathResource(templatePath);
BufferedInputStream bis = new BufferedInputStream(resource.getInputStream());

**
 * {@link Resource} implementation for class path resources. Uses either a
 * given {@link ClassLoader} or a given {@link Class} for loading resources.
 *
 * <p>Supports resolution as {@code java.io.File} if the class path
 * resource resides in the file system, but not for resources in a JAR.
 * Always supports resolution as URL.
 *
 * @author Juergen Hoeller
 * @author Sam Brannen
 * @since 28.12.2003
 * @see ClassLoader#getResourceAsStream(String)
 * @see Class#getResourceAsStream(String)
 */
public class ClassPathResource extends AbstractFileResolvingResource {

* <p>Supports resolution as {@code java.io.File} if the class path
* resource resides in the file system, but not for resources in a JAR.
* Always supports resolution as URL.

InputStream inputStream = this.getClass().getClassLoader().getResource("/script/test.py"
).openStream();
InputStream inputStream = this.getClass().getResourceAsStream("/script/test.py");
InputStream inputStream = this.getClass().getClassLoader().getResourceAsStream("/script/test.py");