Spring Boot开发时Java对象和Json对象之间的转换

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.12.5</version>
</dependency>

import com.fasterxml.jackson.databind.ObjectMapper;
public class ObjectToJson {
    public static void main(String[] args) {
        // 创建一个Java对象
        Person person = new Person("张三", 25);
        // 创建ObjectMapper对象
        ObjectMapper objectMapper = new ObjectMapper();
        try {
            // 将Java对象转换为Json字符串
            String jsonString = objectMapper.writeValueAsString(person);
            System.out.println("Json字符串：" + jsonString);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

public class Person {
    private String name;
    private int age;
    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }
    // getter和setter方法省略...
}

import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
import java.util.Map;
public class JsonToObject {
    public static void main(String[] args) {
        // 创建一个Json字符串（JSON格式）
        String jsonString = "{\"name\":\"张三\",\"age\":25}";
        // 创建ObjectMapper对象
        ObjectMapper objectMapper = new ObjectMapper();
        try {
            // 将Json字符串转换为Map对象（键值对）
            Map<String, Object> map = objectMapper.readValue(jsonString, Map.class);
            Person person = new Person((String) map.get("name"), (Integer) map.get("age"));
            System.out.println("Java对象：" + person);
        } catch (IOException e) {
            e.printStackTrace();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}