Java HashTable的原理与实现

package com.example.demo.javaTest.map;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.test.context.junit4.SpringRunner;
import java.util.Hashtable;
import java.util.Map;
/**
 * @Date 2023-09-09 21:20
 */
@RunWith(SpringRunner.class)
@SpringBootTest(webEnvironment = SpringBootTest.WebEnvironment.RANDOM_PORT)
public class HashTableTest {
    @Test
    public void testHashTable() {
        Map<String, Integer> ht = new Hashtable<>();
        ht.put("A", 18);
        ht.put("B", 21);
        ht.put("C", 45);
        System.out.println(ht.get("A"));            //输出18
        System.out.println(ht.containsKey("B"));    //输出true
        System.out.println(ht.containsValue(45));   //输出true
        ht.remove("C"); //移除key为C的元素
        System.out.println(ht);
    }
}

public class MyObject {
    private String name;
    private int age;
    // 省略构造方法和其他方法
    @Override
    public int hashCode() {
        int result = 17;
        result = 31 * result + name.hashCode();
        result = 31 * result + age;
        return result;
    }
}

    @Test
    public void testContains() {
        Map<String, Integer> ht = new Hashtable<>();
        ht.put("A", 18);
        ht.put("B", 21);
        ht.put("C", 45);
        Assert.assertTrue(ht.containsKey("A"));
        Assert.assertFalse(ht.containsKey("D"));
        Assert.assertTrue(ht.containsValue(21));
        Assert.assertFalse(ht.containsValue(46));
    }

    @Test
    public void testRemove() {
        Map<String, Integer> ht = new Hashtable<>();
        ht.put("A", 25);
        ht.put("B", 21);
        ht.put("C", 35);
        ht.remove("B");
        Assert.assertEquals(Integer.valueOf(25), ht.get("A"));
        Assert.assertNull(ht.get("B"));
        Assert.assertEquals(Integer.valueOf(35), ht.get("C"));
    }