C#连接Mysql数据库详细教程(内附Mysql及Navicat)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using MySql.Data.MySqlClient;
 
namespace DataBaseManager
{
    class connect
    {
        public MySqlConnection conn = null;//连接对象
        public MySqlCommand comm = null;//语句执行对象
        public MySqlDataReader dr = null;//语句执行结果数据对象
 
        //用于一个窗口让用户自定义输入用户名与密码，在这里我直接定义好了
        //public string uid;
        //public string pwd;
 
        public void load()
        {
            //直接写链接语句，比较容易出错
            //conn = new MySqlConnection(
            //    "Database = data;Server = localhost;Port = 3306;Password = " + pwd + ";UserID = " + uid + ";charset = utf8mb4");
            //conn.Open();
 
            //使用Builder写语句，实现分段
            //与数据库连接的信息
            MySqlConnectionStringBuilder builder = new MySqlConnectionStringBuilder();
            //数据库连接时的用户名，可以用pid
            builder.UserID = "root";
            //数据库连接时的密码，可以用pwd
            builder.Password = "admin";
            //数据库连接时的服务器地址
            builder.Server = "localhost";
            //要连接的数据库
            builder.Database = "data";
            //定义与数据连接的链接
            conn = new MySqlConnection(builder.ConnectionString);
            //打开这个链接
            conn.Open();
 
        }
    }
}

 private void button1_Click(object sender, EventArgs e)
        {
            //con.uid = textBox1.Text;
            //con.pwd = textBox2.Text;
 
            //调用load方法建立open连接
            con.load();
            //查询语句，查询用户名与密码，这里的ls可以是textBox1.Text
            string sql = "select * from user_info where username ='ls';";
            con.comm = new MySqlCommand(sql, con.conn);
            con.dr = con.comm.ExecuteReader();
            con.dr.Read();
 
            //验证密码，同理，这里的123可以是textBox2.Text，因为我数据库设置的密码与账号是ls 与 123 所以无论输入什么都是登陆成功
            if ("123" == con.dr.GetString("password"))
            {
                MessageBox.Show("登录成功！");
                con.dr.Close();
                this.Close();//关闭此窗口，方便弹出主窗口
            }
            else
                MessageBox.Show("登录失败！");
        }