Java中的信号量Semaphore详细解读

		Semaphore s = new Semaphore(1);
        s.acquire();
        s.release();

import java.util.concurrent.Semaphore;

public class SemaphoreTest {
    public static void main(String[] args) throws InterruptedException {
        Semaphore t = new Semaphore(1);

        new Thread(  ()->{
            try {
              t.acquire(  );  // 获取
              Thread.sleep(2000);
              System.out.println(Thread.currentThread().getName()+" 执行!");
            } catch (InterruptedException e) {
                e.printStackTrace();
            }finally {
                t.release(); //释放
            }

        } ,"thread1" ).start();

        new Thread(  ()->{
            try {
                t.acquire();
                Thread.sleep(2000);
                System.out.println(Thread.currentThread().getName()+" 执行!");

            } catch (Exception e) {
                e.printStackTrace();
            }finally {
                t.release(1);
            }
        } ,"thread2" ).start();



    }
}