rust如何解析json数据举例详解

[dependencies]
serde = { version = "1.0", features = ["derive"] }
serde_json = "1.0"

use serde::{Deserialize, Serialize};
use serde_json::Result;
#[derive(Serialize, Deserialize)]
struct Person {
    name: String,
    age: u32,
}

fn main() -> Result<()> {
    let john = Person {
        name: "John".to_string(),
        age: 30,
    };
    
     // 将结构体序列化为 JSON 字符串
    let json_string = serde_json::to_string(&john)?;
    println!("Serialized JSON string: {}", json_string);
    
     // 将 JSON 字符串反序列化为结构体
    let deserialized_person: Person = serde_json::from_str(&json_string)?;
    println!("Deserialized Person: {:?}", deserialized_person);
     Ok(())
}

use serde::{Deserialize, Serialize};
 
#[derive(Serialize, Deserialize, Debug)]
struct Persons {
    // #[serde(rename(serialize = "persons", deserialize = "persons"))]
    persons: Vec<Person>,
}
 
#[derive(Serialize, Deserialize, Debug)]
struct Person {
    // #[serde(rename(serialize = "name", deserialize = "name"))]
    name: String,
    // #[serde(rename(serialize = "age", deserialize = "age"))]
    age: i32,
}
 
fn main() -> Result<(), Box<dyn Error>> {
    let json_str = r#"{
        "persons" : [
            {
                "name" : "Joe",
                "age" : 12
            }
        ]
    }"#;
    let v: Persons = serde_json::from_str(&json_str)?;
    println!("{:?}", v);
    let json_str = serde_json::to_string(&v)?;
    println!("{}", json_str);
    let json_str = serde_json::to_string_pretty(&v)?;
    println!("{}", json_str);
 
    Ok(())
}
 
/*
Persons { persons: [Person { name: "Joe", age: 12 }] }
{"persons":[{"name":"Joe","age":12}]}
{
  "persons": [
    {
      "name": "Joe",
      "age": 12
    }
  ]
}
*/