Java如何通过属性名获取Object对象属性值

public Object getPropertyValue(Object t,String objProperty) {
    Map<String, String> objMap = null;
    try {
        objMap = BeanUtils.describe(t);
        return objMap.get(objProperty);
    } catch (Exception e) {
        e.printStackTrace();
    }
    return null;
}

public Object getFieldValueByName(Object o,String fieldName) {
    try {
        String firstLetter = fieldName.substring(0, 1).toUpperCase();
        String getter = "get" + firstLetter + fieldName.substring(1);
        Method method = o.getClass().getMethod(getter);
        return method.invoke(o);
    } catch (Exception e) {
        e.printStackTrace();
    }
    return null;
}

//Map方式
Object obj = getPropertyValue(order, "userId");
if (obj != null) {
    Integer userId = Integer.parseInt((String)obj);
}

//invoke方式
Object obj = getFieldValueByName(order, "userId");
if (obj != null) {
    Integer userId = (Integer)obj;
}

//对象名称,属性名
 
//返回该对象下的数据内容
 
public object GetPropertyValue(object info, string field)
        {
            if (info == null) return null;
            Type t = info.GetType();
    IEnumerable<System.Reflection.PropertyInfo> property = from pi in t.GetProperties() where pi.Name.ToLower() == field.ToLower() select pi;
            return property.First().GetValue(info, null);
        }