C/C++解析文件名和目录路径的方法

#include <stdio.h>
#include <libgen.h>

int main() {
    char path[] = "/home/user/file.txt";
    printf("Base name: %s\n", basename(path)); // 输出: "file.txt"
    return 0;
}

#include <stdio.h>
#include <libgen.h>

int main() {
    char path[] = "/home/user/file.txt";
    printf("Directory name: %s\n", dirname(path)); // 输出: "/home/user"
    return 0;
}

#include <stdio.h>
#include <libgen.h>
#include <string.h>

int main() {
    char path[] = "/home/user/file.txt";

    // 复制原始字符串以避免 basename/dirname 修改它
    char path_copy[256];
    strncpy(path_copy, path, sizeof(path_copy));

    printf("Original path: %s\n", path);
    printf("Base name: %s\n", basename(path_copy)); // 输出: "file.txt"

    // 重新复制原始字符串以获取目录名
    strncpy(path_copy, path, sizeof(path_copy));
    printf("Directory name: %s\n", dirname(path_copy)); // 输出: "/home/user"

    return 0;
}