Java TimeoutException：服务调用超时异常的正确解决方案

import java.util.concurrent.*;

public class ServiceClient {
    public static void main(String[] args) {
        ExecutorService executor = Executors.newSingleThreadExecutor();
        Future<String> future = executor.submit(() -> {
            // 模拟服务调用
            return callRemoteService();
        });

        try {
            // 等待服务响应，设置超时时间为5秒
            String response = future.get(5, TimeUnit.SECONDS);
            System.out.println("Service response: " + response);
        } catch (TimeoutException e) {
            System.err.println("Service call timed out");
        } catch (InterruptedException | ExecutionException e) {
            e.printStackTrace();
        } finally {
            executor.shutdown();
        }
    }

    private static String callRemoteService() {
        // 模拟服务调用延迟
        try {
            Thread.sleep(6000); // 延迟6秒
        } catch (InterruptedException e) {
            Thread.currentThread().interrupt();
        }
        return "Response from service";
    }
}

// 设置更长的超时时间
String response = future.get(10, TimeUnit.SECONDS);

int retryCount = 3;
while (retryCount > 0) {
    try {
        String response = future.get(5, TimeUnit.SECONDS);
        System.out.println("Service response: " + response);
        break;
    } catch (TimeoutException e) {
        retryCount--;
        if (retryCount == 0) {
            throw new RuntimeException("Service call failed after retries");
        }
    }
}