Visual Studio调试技巧与函数递归示例详解

#include <stdio.h>
int main() {
    int a = 5;
    int b = 10;
    int sum = a + b;
    printf("Sum is: %d\n", sum); // 在此行设置断点
    return 0;
}

#include <stdio.h>
int main() {
    for (int i = 0; i < 10; i++) {
        printf("i = %d\n", i); // 在此行设置断点，条件为 i == 5
    }
    return 0;
}

#include <stdio.h>
int factorial(int n) {
    if (n == 0)  // 基本情况
        return 1;
    else
        return n * factorial(n - 1);  // 递归调用
}
int main() {
    int num = 5;
    printf("Factorial of %d is %d\n", num, factorial(num));
    return 0;
}

#include <stdio.h>
int fibonacci(int n) {
    if (n <= 1)
        return n;
    else
        return fibonacci(n - 1) + fibonacci(n - 2);  // 递归调用
}
int main() {
    int n = 10;
    for (int i = 0; i <= n; i++) {
        printf("%d ", fibonacci(i));
    }
    return 0;
}

#include <stdio.h>
void hanoi(int n, char from, char to, char aux) {
    if (n == 1) {
        printf("Move disk 1 from %c to %c\n", from, to);
        return;
    }
    hanoi(n - 1, from, aux, to);
    printf("Move disk %d from %c to %c\n", n, from, to);
    hanoi(n - 1, aux, to, from);
}
int main() {
    int n = 3; // 三个盘子
    hanoi(n, 'A', 'C', 'B');  // A -> C, B为辅助柱
    return 0;
}

#include <stdio.h>
int tailFactorial(int n, int result) {
    if (n == 0)
        return result;
    else
        return tailFactorial(n - 1, n * result);  // 尾递归
}
int main() {
    int num = 5;
    printf("Factorial of %d is %d\n", num, tailFactorial(num, 1));
    return 0;
}