mysql如何分组统计并求出百分比

SELECT
    point_id,
    pname_cn,
    play_num,
    round( play_num / total * 100, 2 ) as `ratio`
FROM
    (
    SELECT
        * 
    FROM
        ( SELECT 
                ANY_VALUE ( `point_id` ) AS point_id, 
                ANY_VALUE ( `pname_cn` ) AS pname_cn,  
                sum( `play` ) AS play_num  
            FROM 
                `dt_collect_antique` WHERE`add_time` BETWEEN '2020-07-02' AND '2020-07-05'  GROUP BY `point_id`  ) t1
            INNER JOIN 
            ( SELECT 
                    sum( `play` ) AS total 
                FROM 
                    `dt_collect_antique` WHERE`add_time` BETWEEN '2020-07-02' AND '2020-07-05'
            ) t2 ON 1 = 1 
    ) t
     
ORDER BY
    `play_num` DESC 
    LIMIT 0, 10;

SELECT 
    ANY_VALUE ( `point_id` ) AS point_id, 
    ANY_VALUE ( `pname_cn` ) AS pname_cn,  
    sum(`like`) as like_num
FROM 
    `dt_collect_antique` WHERE`add_time` BETWEEN '2020-07-02' AND '2020-07-05'  GROUP BY `point_id`  ) t1

(SELECT 
    sum( `play` ) AS total 
FROM 
    `dt_collect_antique` WHERE`add_time` BETWEEN '2020-07-02' AND '2020-07-05'
) t2

SELECT
    age_group,
    age_total,
    round( age_total / total * 100, 2 ) as `ratio`
FROM
    (
       SELECT
        * 
    FROM
        ( SELECT 
               SUM(total) AS age_total,
                   CASE
                    WHEN age >= 0 AND age < 18 THEN '18岁以下'
                    WHEN age >= 18 AND age <= 25 THEN '18岁到25岁'
                    WHEN age >= 26 AND age <= 35 THEN '26岁到35岁'
                    WHEN age >= 36 AND age <= 45 THEN '36岁到45岁'
                    WHEN age >= 46 AND age <= 60 THEN '46岁到60岁'
                   ELSE '60岁以上' END
                AS age_group FROM dt_collect_age WHERE `add_time` BETWEEN ".$time[0]." AND ".$time[1]." GROUP BY age_group
        ) t1
        INNER JOIN 
            ( SELECT 
                   SUM( `total` ) AS total 
               FROM 
                `dt_collect_age` WHERE `add_time` BETWEEN ".$time[0]." AND ".$time[1]."
            ) t2 ON 1 = 1 
           ) t
    LIMIT 0, 6;