MySQL大量脏数据如何只保留最新的一条(最新推荐)

CREATE TABLE `order_cost_detail` (
  `id` int NOT NULL AUTO_INCREMENT COMMENT '主键',
  `order_no` varchar(32)  NOT NULL COMMENT '订单号',
  `cost_id` int NOT NULL COMMENT '费用Id',
  `cost_name` varchar(50)  NOT NULL DEFAULT '' COMMENT '费用名称',
  `money` decimal(10,2) NOT NULL COMMENT '金额',
  `create_time` datetime NOT NULL COMMENT '创建时间',
  `deleted` tinyint(1) NOT NULL COMMENT '是否删除（0 否，1 是）',
  PRIMARY KEY (`id`) USING BTREE
) ENGINE=InnoDB AUTO_INCREMENT=1  COMMENT='订单 - 费用表';

INSERT INTO `order_cost_detail` (`id`, `order_no`, `cost_id`, `cost_name`, `money`, `create_time`, `deleted`)
VALUES
	(1, 'EX202208160000012-3', 2, '停车费', 100.00, '2022-08-19 11:30:48', 0),
	(2, 'EX202208160000012-4', 3, '停车费', 100.00, '2023-02-17 11:25:27', 0),
	(3, 'EX202208160000012-4', 3, '停车费', 200.00, '2023-02-17 11:25:28', 0),
	(4, 'EX202208170000002-1', 1, '路桥费', 300.00, '2022-08-19 11:31:57', 0),
	(5, 'EX202208170000002-1', 1, '路桥费', 450.00, '2022-08-19 11:32:57', 0),
	(6, 'EX202208180000002-1', 2, '高速费', 225.00, '2022-08-19 11:35:41', 0);

SELECT order_no, cost_name, count(*) AS num
FROM order_cost_detail
WHERE deleted = 0
GROUP BY order_no, cost_name
HAVING num > 1

select *
from order_cost_detail
where id not in (
	select max(id) as num
	from order_cost_detail
	where deleted = 0
	group by order_no, cost_name
)

-- 这里是逻辑删除，也就是将需要删除的数据打上deleted = 1 标记
update order_cost_detail
set deleted = 1
where id in (
select id from order_cost_detail where id not in (
select max(id) as num from order_cost_detail where deleted = 0 group by order_no, cost_name
		)
	)

update order_cost_detail
set deleted = 1
where id in (
select t.id
from
( 
select id from order_cost_detail where id not in (
select max(id) as num from order_cost_detail where deleted = 0 group by order_no, cost_name )
	) t
)