MYSQL如何查询成绩为前5名的学生

select * from table where name="panpan"

select * from table where name="panpan" limit 1

select * from table order by grade

select * from score order by grade limit 5

-- ----------------------------
-- Table structure for grade
-- ----------------------------
DROP TABLE IF EXISTS `grade`;
CREATE TABLE `grade` (
  `stu_name` varchar(255) NOT NULL,
  `stu_subject` varchar(255) NOT NULL,
  `score` int(255) DEFAULT NULL,
  PRIMARY KEY (`stu_subject`,`stu_name`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

-- ----------------------------
-- Records of grade
-- ----------------------------
INSERT INTO `grade` VALUES ('lilei', 'shuxue', '99');
INSERT INTO `grade` VALUES ('xiaoyong', 'shuxue', '66');
INSERT INTO `grade` VALUES ('lilei', 'yingyu', '80');
INSERT INTO `grade` VALUES ('xiaoyong', 'yingyu', '55');
INSERT INTO `grade` VALUES ('lilei', 'yuwen', '78');
INSERT INTO `grade` VALUES ('xiaoyong', 'yuwen', '88');

SELECT grade.stu_subject, MAX(grade.score) as score from grade GROUP BY stu_subject;

SELECT grade.* from grade,
(SELECT grade.stu_subject, MAX(grade.score) as score from grade GROUP BY stu_subject )b
WHERE grade.score = b.score and grade.stu_subject = b.stu_subject;

SELECT “成绩最高”,grade.* from grade,
(SELECT grade.stu_subject, MAX(grade.score) as score from grade GROUP BY stu_subject )b
WHERE grade.score = b.score and grade.stu_subject = b.stu_subject;

SELECT "成绩最高",grade.* from grade, 
(SELECT  grade.stu_subject, MAX(grade.score) as score  from grade GROUP BY  stu_subject  )b
WHERE grade.score = b.score and grade.stu_subject = b.stu_subject
UNION
SELECT "成绩最低",grade.* from grade, 
(SELECT  grade.stu_subject, MIN(grade.score) as score  from grade GROUP BY  stu_subject  )b
WHERE grade.score = b.score and grade.stu_subject = b.stu_subject;