Python Redis如何执行Lua脚本

pip install redis

from redis import Redis

redis = Redis()
script = """
redis.call('SETEX', 'key', 100, 'value')
"""
redis.register_script(script)()  # 执行脚本

def __call__(self, keys=[], args=[], client=None)

from redis import Redis

redis = Redis()
script = """
local key = KEYS[1]
local seconds = ARGV[1]
local value = ARGV[2]
redis.call('SETEX', key, seconds, value)
"""
cmd = redis.register_script(script)
cmd(keys=['key'], args=[100, 'value'])  # 执行脚本

import time
from uuid import uuid4

from redis import Redis

redis = Redis()

# 判断是否自己创建的锁，是的话则释放
script = """
if redis.call('GET', KEYS[1]) == ARGV[1] then
    return redis.call('DEL', KEYS[1])
else
    return 0
end
"""


def do_something():
    name = 'lock'  # 锁名，此处故意写死让别的进程进来占用
    uuid = str(uuid4())
    # 上锁
    if redis.set(name=name, value=uuid, nx=True, ex=25):  # 锁不存在才能上锁成功，过期时间应为业务时间的五倍，此处故意写小，模拟过期释放
        print('上锁')
        try:
            print('处理业务', uuid)
            time.sleep(10)
        except Exception as e:
            print(e)
        finally:
            # 释放锁
            cmd = redis.register_script(script)
            res = cmd(keys=[name], args=[uuid])  # 执行脚本
            if res:
                print('锁已释放')
            else:
                print('不是自己的锁')
    else:
        print('锁已存在')


if __name__ == '__main__':
    do_something()