oracle/mysql数据库多条重复数据如何取最新的

select * from table_name
WHERE id in (
select max(id) id from table_name GROUP BY 分组字段)

SELECT r.*
FROM records r
INNER JOIN (
    SELECT group_id, MAX(timestamp) as latest
    FROM records
    GROUP BY group_id
) as latest_records 
ON r.group_id = latest_records.group_id 
AND r.timestamp = latest_records.latest;

SELECT *  
FROM (  
    SELECT t.*,  
           ROW_NUMBER() OVER (PARTITION BY LOCALAUTHID ORDER BY LASTUPDATETIME DESC) AS rn  
    FROM USER_LOCALAUTH_STATE t  
) t  
WHERE t.rn = 1;

SELECT *  
FROM (  
    SELECT t.*,ROW_NUMBER() OVER (PARTITION BY LOCALAUTHID ORDER BY LASTUPDATETIME DESC) AS rn  
    FROM    
		(
			-- 筛选存在重复的数据，count(LOCALAUTHID) > 1
			select * from USER_LOCALAUTH_STATE
			where LOCALAUTHID	in (
				SELECT LOCALAUTHID
				FROM USER_LOCALAUTH_STATE WHERE STATE = 1 AND BUSINESSTYPE=1
				group by LOCALAUTHID having count(LOCALAUTHID) > 1)
		) t
	) rt  
WHERE rt.rn = 1;

select * from (select row_number() over (partition by certno order by consigndate) rn, a.* from US_ADDCONSIGN a where 1=1 and state=1 ) where rn=1 and to_date(consigndate,'yyyymmdd')<to_date('20210101','yyyymmdd');