mysql空间函数计算坐标距离方式

DROP TABLE IF EXISTS `teacher`;
CREATE TABLE `teacher`  (
  `id` int NOT NULL AUTO_INCREMENT,
  `name` varchar(50) CHARACTER SET utf8 COLLATE utf8_general_ci NOT NULL,
  `longitude` decimal(9, 6) NULL DEFAULT NULL,
  `latitude` decimal(9, 6) NULL DEFAULT NULL,
  `address` varchar(100) CHARACTER SET utf8mb4 COLLATE utf8mb4_general_ci NULL DEFAULT NULL,
  PRIMARY KEY (`id`) USING BTREE
) ENGINE = InnoDB AUTO_INCREMENT = 4 CHARACTER SET = utf8mb4 COLLATE = utf8mb4_general_ci ROW_FORMAT = Dynamic;

-- ----------------------------
-- Records of teacher
-- ----------------------------
INSERT INTO `teacher` VALUES (1, '张三', 116.397755, 39.903179, '天安门');
INSERT INTO `teacher` VALUES (2, '李四', 116.397029, 39.917840, '故宫');
INSERT INTO `teacher` VALUES (3, '王五', 116.190595, 39.876665, '园博园');
INSERT INTO `teacher` VALUES (4, '赵六', 116.410829, 39.881983, '天坛公园');

SELECT
	*,
	ROUND( st_distance ( point ( longitude, latitude ), point ( 116.393823, 39.905024 ))* 111195, 2 ) dis 
FROM
	teacher

SELECT
	*,
	round( st_distance_sphere ( point ( 116.393823, 39.905024 ), point ( `longitude`, `latitude` ) ), 2 ) dis 
FROM
	teacher 
ORDER BY
	dis